CBSE Class 11 Chemistry Chapter 11: The p-Block Elements NCERT Solutions

NCERT Solutions PDF Class 11 PDF

CBSE Class 11 Chemistry Chapter 11, p-Block Elements, NCERT Solutions, explores the fascinating trends in oxidation states across Group 13 (Boron to Thallium) and Group 14 (Carbon to Lead). We'll uncover the underlying reasons for these variations, including the significant role of the inert pair effect. The solutions also address key chemical behaviours, such as the Lewis acidic nature of Boron Trifluoride, attributed to its electron-deficient structure. This chapter aims to demystify the complexities of p-block elements, providing clear explanations to solidify your understanding of inorganic chemistry and enhance your exam preparation.

Quick info

BoardCBSE
ClassClass 11
SubjectChemistry
Session2026
LanguageEnglish
TypeNCERT Solutions
ChapterChapter 11

Chapter summary

Chapter 11, 'The p-Block Elements,' for Class 11 Chemistry, focuses on the trends in properties of elements in groups 13 and 14. The NCERT Solutions provided here explain the variation in oxidation states, the concept of the inert pair effect, and the Lewis acidic nature of compounds like BF3. These solutions offer step-by-step explanations to help students grasp the fundamental concepts of p-block elements.

Learning outcomes

  • Understand the variation in oxidation states of Group 13 and Group 14 elements.
  • Explain the stability of different oxidation states based on the inert pair effect.
  • Identify and explain the Lewis acidic nature of compounds like Boron Trifluoride.
  • Relate electronic configuration to the chemical behavior of p-block elements.

Topics covered

Paper topics

  • p-Block Elements
  • Group 13 Elements
  • Group 14 Elements
  • Oxidation States
  • Variation in Oxidation States
  • Inert Pair Effect
  • Boron Trifluoride (BF3)
  • Lewis Acid
  • Electronic Configuration
  • Stability of Oxidation States
  • Boron
  • Thallium

Important topics

  • Variation in oxidation states of Group 13 and 14
  • Inert pair effect
  • Lewis acidity of BF3
  • Stability trends of oxidation states

PDF preview

Read page by page below. PDF is streamed from the official NCERT website — no download button on this page.

Loading document …
Page of
Loading page …

Questions and Solutions

Question 11.1

Discuss the pattern of variation in the oxidation states of
  1. B to Tl and
  2. C to Pb
Solution:

The variation in oxidation states for the given groups is explained as follows:

(i) Boron (B) to Thallium (Tl) - Group 13 Elements

The general electronic configuration for Group 13 elements is ns^2 np^1. Consequently, the most common oxidation state exhibited by these elements is expected to be +3, involving all three valence electrons. However, this trend is not uniform across the group.

  • Boron (B) and Aluminium (Al): These elements predominantly exhibit the +3 oxidation state.
  • Gallium (Ga), Indium (In), and Thallium (Tl): These heavier elements show both +1 and +3 oxidation states.

A significant trend observed is that as we move down the group from Ga to Tl, the +1 oxidation state becomes increasingly stable, while the +3 oxidation state becomes less stable. This phenomenon is attributed to the **inert pair effect**. The two electrons in the ns orbital are held more tightly by the nucleus and are less likely to participate in bonding. This effect becomes more pronounced in heavier elements.

For example:

  • Ga(+1) is relatively unstable.
  • In(+1) is fairly stable.
  • Tl(+1) is very stable and is the most common oxidation state for Thallium.

Conversely, the stability of the +3 oxidation state decreases as we move down the group.

Summary Table for Group 13:

Element Oxidation State
B +3
Al +3
Ga, In, Tl +1, +3 (stability of +1 increases down the group)

(ii) Carbon (C) to Lead (Pb) - Group 14 Elements

The general electronic configuration for Group 14 elements is ns^2 np^2. The expected common oxidation state is +4, utilizing all four valence electrons. However, similar to Group 13, the stability of oxidation states changes down the group.

  • Carbon (C) and Silicon (Si): These elements primarily exhibit the +4 oxidation state.
  • Germanium (Ge), Tin (Sn), and Lead (Pb): These heavier elements display both +2 and +4 oxidation states.

The **inert pair effect** is also responsible for the observed trend in Group 14. As we move down the group, the stability of the +2 oxidation state increases, while the stability of the +4 oxidation state decreases. This is because the two ns electrons become increasingly reluctant to participate in bonding.

Therefore, while C and Si predominantly exist in the +4 state, Ge, Sn, and Pb show a greater tendency to exist in the +2 state. For instance, Pb(+2) is more stable than Pb(+4).

Summary Table for Group 14:

Element Oxidation State
C +4
Si +4
Ge, Sn, Pb +2, +4 (stability of +2 increases down the group; stability of +4 decreases)

Question 11.2

How can you explain the higher stability of BCl<sub>3</sub> as compared to TlCl<sub>3</sub>?
Solution:

Boron (B) and Thallium (Tl) are both members of Group 13 of the periodic table. A key trend in this group is that the stability of the +1 oxidation state increases, while the stability of the +3 oxidation state decreases as we move down the group, primarily due to the inert pair effect.

Boron, being at the top of the group, readily exhibits its +3 oxidation state, and compounds like BCl<sub>3</sub> are stable in this state. In contrast, Thallium is at the bottom of the group. For Thallium, the +1 oxidation state is significantly more stable than the +3 oxidation state because of the strong inert pair effect.

Consequently, TlCl<sub>3</sub> is less stable than BCl<sub>3</sub>. In fact, Tl(+3) compounds are strong oxidizing agents and tend to revert to the more stable Tl(+1) state. Therefore, BCl<sub>3</sub> is considerably more stable than TlCl<sub>3</sub>.

Question 11.3

Why does boron trifluoride behave as a Lewis acid?
Solution:

Boron trifluoride (BF<sub>3</sub>) behaves as a Lewis acid because the central boron atom is electron-deficient. Let's look at the electronic configuration and bonding:

  • The electronic configuration of Boron is 1s^2 2s^2 2p^1. It has 3 valence electrons.
  • In BF<sub>3</sub>, Boron forms three covalent bonds with three Fluorine atoms. Each bond involves one electron from Boron and one from Fluorine.
  • This means Boron uses all its 3 valence electrons to form bonds.
  • As a result, the Boron atom in BF<sub>3</sub> is surrounded by only 6 valence electrons (3 bonds x 2 electrons/bond), instead of the stable octet of 8 electrons.

Since the boron atom has an incomplete octet, it is electron-deficient and has a strong tendency to accept a pair of electrons to achieve a stable octet configuration. According to the Lewis definition, a substance that can accept an electron pair is called a Lewis acid. Therefore, BF<sub>3</sub> acts as a Lewis acid.

The vacant p-orbital on the Boron atom is available to accept the electron pair.

Boron Trifluoride structure showing vacant p-orbital

Common mistakes

  • Confusing the trend of stability for +1 and +3 oxidation states in Group 13.
  • Misunderstanding the impact of the inert pair effect on oxidation state stability.
  • Not recognizing the reason for Lewis acidity in electron-deficient compounds.

Revision tips

  • Focus on the 'inert pair effect' and how it influences oxidation states down a group.
  • Memorize the general electronic configurations of Group 13 and 14 elements.
  • Understand the electron deficiency concept for Lewis acid behavior.
  • Review the stability trends of oxidation states for both groups.

Practice MCQs

Q1. Which phenomenon explains the increasing stability of the +1 oxidation state down Group 13?

Q2. Which element in Group 13 primarily exhibits the +3 oxidation state?

Q3. In Group 14, which oxidation state becomes more common as we move down the group?

Q4. Why is Boron Trifluoride (BF3) considered a Lewis acid?

Q5. Which statement best describes the stability of oxidation states in Thallium (Tl)?

Frequently asked questions

What are the main topics covered in the NCERT Solutions for Class 11 Chemistry Chapter 11?

These solutions cover the variation in oxidation states for Group 13 (Boron to Thallium) and Group 14 (Carbon to Lead) elements, explaining trends like the inert pair effect and the Lewis acidic nature of compounds such as Boron Trifluoride.

How does the inert pair effect influence oxidation states in p-block elements?

The inert pair effect causes the s-electrons in the valence shell to become less available for bonding as we move down a group. This makes the lower oxidation state (+2 for Group 14, +1 for Group 13) more stable than the higher one (+4 for Group 14, +3 for Group 13).

Why is Boron Trifluoride (BF3) a Lewis acid?

BF3 is a Lewis acid because the boron atom in it has an incomplete octet, possessing only six valence electrons. This electron deficiency allows BF3 to accept an electron pair from a Lewis base.

Are the questions in these solutions the same as in the NCERT textbook?

Yes, the questions are kept exactly the same as in the NCERT textbook, including their numbering and problem statement. The wording has been expanded for clarity where needed.

How do these solutions help in exam preparation?

These solutions provide clear, step-by-step explanations for each question, helping students understand the underlying concepts of p-block elements, trends in oxidation states, and chemical properties, which is crucial for effective exam revision.

Content reviewed by the NCERT Help team. Editorial Team and update policy

NCERT Solutions PDF PDF on NCERT Help. URL unchanged for search indexing.