CBSE Class 12 Chemistry Chapter 6: General Principles and Processes of Isolation of Elements - NCERT Solutions

NCERT Solutions PDF Class 12 PDF

CBSE Class 12 Chemistry, Chapter 6, delves into the General Principles and Processes of Isolation of Elements. This chapter explores various methods used in metallurgy, such as magnetic separation for ores like iron. It highlights the importance of leaching, particularly in the Bayer's process for extracting aluminium from bauxite ore, where sodium hydroxide is used to dissolve the ore. The solutions also examine the thermodynamic feasibility of reduction reactions, comparing the effectiveness of aluminium in reducing chromium oxide versus the reverse reaction. Furthermore, it investigates the conditions under which magnesium can reduce silicon dioxide and the inverse scenario where silicon reduces magnesium oxide. Understanding these principles is vital for comprehending how metals are extracted and purified, offering a solid foundation for students preparing for their examinations.

Quick info

BoardCBSE
ClassClass 12
SubjectChemiry
Session2026
LanguageEnglish
TypeNCERT Solutions
ChapterChapter 6: General Principles and Processes of Isolation of Elements - Intext Questions Solutions

Chapter summary

NCERT Solutions for Class 12 Chemistry, Chapter 6, "General Principles and Processes of Isolation of Elements," offers explanations for intext questions. It covers ore concentration techniques like magnetic separation, the detailed process of leaching in aluminium extraction (Bayer's process), and the thermodynamic feasibility of redox reactions in metal extraction. The solutions also address the conditions required for the reduction of metal oxides by other elements, providing a foundational understanding of metallurgical principles.

Learning outcomes

  • Understand the principle of magnetic separation for ore concentration.
  • Explain the significance and steps of leaching in the extraction of aluminium.
  • Analyze the thermodynamic feasibility of metal extraction reactions.
  • Identify the conditions required for the reduction of metal oxides by other elements.

Topics covered

Paper topics

  • Ore Concentration
  • Magnetic Separation
  • Leaching
  • Bayer's Process
  • Extraction of Aluminium
  • Thermodynamic Feasibility
  • Gibbs Free Energy
  • Reduction of Metal Oxides
  • Metallurgy
  • Chemical Principles

Important topics

  • Magnetic Separation Principle
  • Bayer's Process for Aluminium
  • Thermodynamic Feasibility of Extraction
  • Conditions for Reduction Reactions

PDF preview

Read page by page below. PDF is streamed from the official NCERT website — no download button on this page.

Loading document …
Page of
Loading page …

Questions and Solutions

Question 6.1

Which of the ores mentioned in Table 6.1 can be concentrated by magnetic separation method?
Solution: The magnetic separation method is applicable for concentrating ores if either the ore itself or the impurities (gangue) exhibits magnetic properties. This allows for their separation using a magnetic field. Based on common knowledge of ores listed in such tables, iron ores like haematite ($Fe_2O_3$), magnetite ($Fe_3O_4$), siderite ($FeCO_3$), and iron pyrites ($FeS_2$) possess magnetic properties or are associated with magnetic impurities, making them amenable to concentration via magnetic separation.

Question 6.2

What is the significance of leaching in the extraction of aluminium?
Solution: In the extraction of aluminium, leaching plays a crucial role in purifying the bauxite ore by concentrating pure alumina ($Al_2O_3$). Bauxite ore often contains impurities such as silica ($SiO_2$), iron oxide ($Fe_2O_3$), and titanium oxide ($TiO_2$). The process involves digesting the powdered bauxite ore with a concentrated solution of sodium hydroxide ($NaOH$) at elevated temperatures (473-523 K) and pressure (35-36 bar). Under these conditions, the amphoteric alumina dissolves to form sodium meta-aluminate, while the acidic silica dissolves as sodium silicate. Basic impurities like iron oxide and titanium oxide remain undissolved.

The relevant chemical reactions are:

Al_2O_{3(s)} + 2 NaOH_{(aq)} + 3 H_2O_{(l)} \xrightarrow{473-523 \text{ K}} 2 Na[Al(OH)_4]_{(aq)}

Alumina reacts with sodium hydroxide and water to form soluble sodium tetrahydroxoaluminate.

SiO_{2(s)} + 2 NaOH_{(aq)} \xrightarrow{473-523 \text{ K}} Na_2SiO_{3(aq)} + H_2O_{(l)}

Silica reacts with sodium hydroxide to form soluble sodium silicate.

The insoluble impurities are then filtered off. The filtrate, containing sodium meta-aluminate and sodium silicate, is treated by passing carbon dioxide ($CO_2$) gas. This neutralizes the solution and causes the precipitation of hydrated alumina, while sodium silicate remains in solution.

2 Na[Al(OH)_4]_{(aq)} + CO_{2(g)} \longrightarrow Al_2O_3 \cdot xH_2O_{(s)} + 2 NaHCO_{3(aq)}

Precipitation is often aided by seeding the solution with a small amount of pre-existing hydrated alumina. The precipitated hydrated alumina is then filtered, washed, dried, and strongly heated (calcined) to obtain pure alumina ($Al_2O_3$).

Al_2O_3 \cdot xH_2O_{(s)} \xrightarrow{1470 \text{ K}} Al_2O_{3(s)} + xH_2O_{(g)}

Thus, leaching is essential for separating alumina from its common impurities in the bauxite ore.

Question 6.3

The reaction, Cr_2O_3 + 2Al \longrightarrow Al_2O_3 + 2Cr (\Delta G_0 = -421 \text{ kJ}) is thermodynamically feasible as is apparent from the Gibbs energy value. Why does it not take place at room temperature?
Solution: The given reaction, the reduction of chromium(III) oxide ($Cr_2O_3$) by aluminium ($Al$), is thermodynamically feasible because the standard Gibbs free energy change ($\Delta G_0$) is highly negative (-421 kJ). This indicates that the reaction is spontaneous under standard conditions.

However, the reaction does not occur at room temperature primarily because all the reactants ($Cr_2O_3$ and $Al$) and the products ($Al_2O_3$ and $Cr$) are in the solid state at room temperature. For a reaction to proceed, there needs to be an interaction between the reacting species, and in the solid state, the rate of reaction is extremely slow due to limited mobility and contact. Equilibrium between reactants and products is not effectively established at room temperature in the solid phase.

The relationship between Gibbs free energy ($\Delta G$), enthalpy change ($\Delta H$), and entropy change ($\Delta S$) is given by the equation: \Delta G = \Delta H - T \Delta S. While $\Delta G^0$ is negative, indicating feasibility, the activation energy barrier for the reaction in the solid state is very high at room temperature. At higher temperatures, the reactants gain sufficient kinetic energy to overcome this barrier. Furthermore, as temperature increases, the term $T\Delta S$ becomes more significant. If the entropy change ($\Delta S$) is positive (which is often the case when solids react to form products that might have more disorder or if melting occurs), the $-T\Delta S$ term becomes more negative, further decreasing $\Delta G$ and increasing the feasibility of the reaction. When chromium melts at higher temperatures, the reaction proceeds readily, yielding molten chromium.

Question 6.4

Is it true that under certain conditions, Mg can reduce $SiO_2$ and Si can reduce MgO? What are those conditions?
Solution: Yes, it is true that under certain conditions, magnesium ($Mg$) can reduce silicon dioxide ($SiO_2$), and silicon ($Si$) can reduce magnesium oxide ($MgO$). These reductions are possible due to the relative electrochemical potentials and the conditions under which the reactions are carried out, primarily high temperatures.

1. Mg reducing $SiO_2$:

Magnesium is a highly reactive metal and can reduce silicon dioxide to silicon at elevated temperatures. This reaction is thermodynamically favorable at high temperatures. The condition required is that the reactants must be heated to a sufficiently high temperature, typically above the melting point of magnesium, to allow for effective reaction. The reaction can be represented as:

2Mg_{(l)} + SiO_{2(l)} \longrightarrow 2MgO_{(s)} + Si_{(s)}

This process requires high temperatures where both $Mg$ and $SiO_2$ are in a reactive state (e.g., molten).

2. Si reducing MgO:

Conversely, silicon can act as a reducing agent for magnesium oxide ($MgO$) at very high temperatures. This is related to the Ellingham diagram, which shows that at sufficiently high temperatures, the free energy of formation of $SiO_2$ becomes more negative than that of $MgO$, indicating that $Si$ can displace $Mg$ from $MgO$. The condition is again high temperature, where silicon can effectively reduce magnesium oxide. The reaction can be represented as:

2Si_{(s)} + 2MgO_{(s)} \longrightarrow 2Mg_{(g)} + SiO_{2(s)}

In summary, both reactions are possible but require specific high-temperature conditions where the thermodynamic stability of the oxides shifts, allowing for the reduction to occur.

Common mistakes

  • Confusing the conditions for magnetic separation.
  • Not fully explaining the role of leaching in purifying bauxite.
  • Misinterpreting the influence of temperature on Gibbs free energy and reaction feasibility.
  • Failing to specify the exact conditions (temperature) for reduction reactions.

Revision tips

  • Review the conditions under which magnetic separation is applicable.
  • Memorize the key chemical reactions in the Bayer's process for aluminium extraction.
  • Understand the relationship between Gibbs free energy, temperature, and reaction spontaneity.
  • Focus on the specific temperature ranges required for the reduction of metal oxides.

Practice MCQs

Q1. Which of the following ores can be concentrated using magnetic separation?

Q2. What is the primary purpose of leaching in the extraction of aluminium from bauxite?

Q3. The reaction $Cr_2O_3 + 2Al \rightarrow Al_2O_3 + 2Cr$ is thermodynamically feasible because:

Q4. Why does the reaction $Cr_2O_3 + 2Al \rightarrow Al_2O_3 + 2Cr$ not occur at room temperature?

Q5. Under what condition can Mg reduce $SiO_2$?

Frequently asked questions

What is magnetic separation and which ores can be concentrated using it?

Magnetic separation is a method used to concentrate ores when either the ore or the gangue is magnetic. Ores of iron like haematite and magnetite can be concentrated using this method.

What is the role of leaching in the extraction of aluminium?

Leaching in aluminium extraction (Bayer's process) is significant for concentrating pure alumina ($Al_2O_3$) from bauxite ore by dissolving it in a concentrated NaOH solution, leaving impurities behind.

Why is the reaction $Cr_2O_3 + 2Al \rightarrow Al_2O_3 + 2Cr$ feasible but doesn't occur at room temperature?

The reaction is thermodynamically feasible due to a negative Gibbs free energy change. However, it doesn't occur at room temperature because the reactants and products are solids, and equilibrium is not established. It requires higher temperatures.

How does temperature affect the feasibility of a reaction like the reduction of $Cr_2O_3$ by Al?

Increasing the temperature makes the $T\Delta S$ term more significant and negative, thus making the overall Gibbs free energy ($\Delta G = \Delta H - T\Delta S$) more negative and the reaction increasingly feasible.

What conditions are necessary for Mg to reduce $SiO_2$?

Magnesium can reduce silicon dioxide ($SiO_2$) under conditions of high temperature, typically when $SiO_2$ is molten and Mg is also molten or vaporized, facilitating the reaction.

Can silicon reduce magnesium oxide (MgO)? If so, under what conditions?

Yes, silicon can reduce magnesium oxide (MgO) at high temperatures. The specific conditions involve high temperatures where both reactants can participate effectively in the reduction process.

Content reviewed by the NCERT Help team. Editorial Team and update policy

NCERT Solutions PDF PDF on NCERT Help. URL unchanged for search indexing.