NCERT Solutions for Class 11 Maths Chapter 9 Sequences and Series — Exercise 9.3

Question 1:Find the 20th and nth terms of the G.P. 5 5 5 2 4 8 , , , ...

Question 2:Find the 12th term of a G.P. whose 8th term is 192 and the common ratio is 2.

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Question 3:The 5th, 8th and 11th terms of a G.P. are p, q and s, respectively. Show that q2 = ps.

Question 4:The 4th term of a G.P. is square of its second term, and the first term is – 3. Determine its 7th term.

Question 5:Which term of the following sequences: (a) 2,2 2,4,... is 128 ? (b) 3,3,3 3,... is729 ? (c) 1 1 1 1 is 3 9 27 19683 , , ,... ?

Exercise 9.3 maths class 11 Chapter 9 Sequences and Series

Question 6:For what values of x, the numbers 2 7 7 2 – , x, – are in G.P.? Find the sum to indicated number of terms in each of the geometric progressions in Exercises 7 to 10:

Question 7:0.15, 0.015, 0.0015, ... 20 terms.

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Question 8:7 , 21 , 3 7 , ... n terms.

Question 9:1, – a, a2, – a3, ... n terms (if a ¹ – 1).

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Question 10:x3, x5, x7, ... n terms (if x ¹ ± 1).

Question 11:Evaluate 11 1 (2 3 ) k k= å + .

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Question 12:The sum of first three terms of a G.P. is 39 10 and their product is 1. Find the common ratio and the terms.

Question 13:How many terms of G.P. 3, 32, 33, … are needed to give the sum 120?

Question 14:The sum of first three terms of a G.P. is 16 and the sum of the next three terms is 128. Determine the first term, the common ratio and the sum to n terms of the G.P.

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Question 15:Given a G.P. with a = 729 and 7th term 64, determine S7.

Question 16:Find a G.P. for which sum of the first two terms is – 4 and the fifth term is 4 times the third term.

Question 17:If the 4th, 10th and 16th terms of a G.P. are x, y and z, respectively. Prove that x, y, z are in G.P.

Question 18:Find the sum to n terms of the sequence, 8, 88, 888, 8888… .

Exercise 9.3 class 11 Math ncert solutions Chapter 9

Question 19:Find the sum of the products of the corresponding terms of the sequences 2, 4, 8, 16, 32 and 128, 32, 8, 2, 1 2 .

Question 20:Show that the products of the corresponding terms of the sequences a, ar, ar2, …arn – 1 and A, AR, AR2, … ARn – 1 form a G.P, and find the common ratio.

Question 21:Find four numbers forming a geometric progression in which the third term is greater than the first term by 9, and the second term is greater than the 4th by 18.

EXERCISE 9.31. Find the 20th and nth terms of the

Question 22:If the pth, qth and rth terms of a G.P. are a, b and c, respectively. Prove that aq – r br – pcP – q = 1.

Question 23:If the first and the nth term of a G.P. are a and b, respectively, and if P is the product of n terms, prove that P2 = (ab)n.

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Question 24:Show that the ratio of the sum of first n terms of a G.P. to the sum of terms from (n + 1)th to (2n)th term is 1 n r .

Question 25:If a, b, c and d are in G.P. show that (a2 + b2 + c2) (b2 + c2 + d2) = (ab + bc + cd)2 .

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Question 26:Insert two numbers between 3 and 81 so that the resulting sequence is G.P.

Question 27:Find the value of n so that a b a b n n n n + + + + 1 1 may be the geometric mean between a and b.

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Question 28:The sum of two numbers is 6 times their geometric mean, show that numbers are in the ratio (3+ 2 2): (3−2 2).

Question 29:If A and G be A.M. and G.M., respectively between two positive numbers, prove that the numbers are A ± (A+G )(A−G ) .

Question 30:The number of bacteria in a certain culture doubles every hour. If there were 30 bacteria present in the culture originally, how many bacteria will be present at the end of 2nd hour, 4th hour and nth hour ?

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Question 31:What will Rs 500 amounts to in 10 years after its deposit in a bank which pays annual interest rate of 10% compounded annually?

Question 32:If A.M. and G.M. of roots of a quadratic equation are 8 and 5, respectively, then obtain the quadratic equation.